Infinite sums and products over ℕ
and ℤ
#
This file contains lemmas about HasSum
, Summable
, tsum
, HasProd
, Multipliable
, and tprod
applied to the important special cases where the domain is ℕ
or ℤ
. For instance, we prove the
formula ∑ i in range k, f i + ∑' i, f (i + k) = ∑' i, f i
, in sum_add_tsum_nat_add
, as well as
several results relating sums and products on ℕ
to sums and products on ℤ
.
Sums over ℕ
#
If f : ℕ → M
has sum m
, then the partial sums ∑ i in range n, f i
converge
to m
.
If f : ℕ → M
has product m
, then the partial products ∏ i in range n, f i
converge
to m
.
If f : ℕ → M
is summable, then the partial sums ∑ i in range n, f i
converge
to ∑' i, f i
.
If f : ℕ → M
is multipliable, then the partial products ∏ i in range n, f i
converge
to ∏' i, f i
.
You can compute a sum over an encodable type by summing over the natural numbers and taking a supremum. This is useful for outer measures.
You can compute a product over an encodable type by multiplying over the natural numbers and taking a supremum.
tsum_iSup_decode₂
specialized to the complete lattice of sets.
tprod_iSup_decode₂
specialized to the complete lattice of sets.
Some properties about measure-like functions. These could also be functions defined on complete
sublattices of sets, with the property that they are countably sub-additive.
R
will probably be instantiated with (≤)
in all applications.
If a function is countably sub-additive then it is sub-additive on countable types
If a function is countably sub-multiplicative then it is sub-multiplicative on countable types
If a function is countably sub-additive then it is sub-additive on finite sets
If a function is countably sub-multiplicative then it is sub-multiplicative on finite sets
If a function is countably sub-additive then it is binary sub-additive
If a function is countably sub-multiplicative then it is binary sub-multiplicative
For f : ℕ → G
, the sum ∑' k, f (k + i)
tends to zero. This does not require a
summability assumption on f
, as otherwise all such sums are zero.
For f : ℕ → G
, the product ∏' k, f (k + i)
tends to one. This does not require a
multipliability assumption on f
, as otherwise all such products are one.
Sums over ℤ
#
In this section we prove a variety of lemmas relating sums over ℕ
to sums over ℤ
.
Alias of HasSum.of_nat_of_neg_add_one
.
If f₀, f₁, f₂, ...
and g₀, g₁, g₂, ...
have sums a
, b
respectively, then
the ℤ
-indexed sequence: ..., g₂, g₁, g₀, f₀, f₁, f₂, ...
(with f₀
at the 0
-th position) has
sum a + b
.
If f₀, f₁, f₂, ...
and g₀, g₁, g₂, ...
have products a
, b
respectively, then
the ℤ
-indexed sequence: ..., g₂, g₁, g₀, f₀, f₁, f₂, ...
(with f₀
at the 0
-th position) has
product a + b
.
If f₀, f₁, f₂, ...
and g₀, g₁, g₂, ...
are both summable then so is the
ℤ
-indexed sequence: ..., g₂, g₁, g₀, f₀, f₁, f₂, ...
(with f₀
at the 0
-th position).
If f₀, f₁, f₂, ...
and g₀, g₁, g₂, ...
are both multipliable then so is the
ℤ
-indexed sequence: ..., g₂, g₁, g₀, f₀, f₁, f₂, ...
(with f₀
at the 0
-th position).
If f₀, f₁, f₂, ...
and g₀, g₁, g₂, ...
are both summable, then the sum of the
ℤ
-indexed sequence: ..., g₂, g₁, g₀, f₀, f₁, f₂, ...
(with f₀
at the 0
-th position) is
∑' n, f n + ∑' n, g n
.
If f₀, f₁, f₂, ...
and g₀, g₁, g₂, ...
are both multipliable, then the product of the
ℤ
-indexed sequence: ..., g₂, g₁, g₀, f₀, f₁, f₂, ...
(with f₀
at the 0
-th position) is
(∏' n, f n) * ∏' n, g n
.
Alias of HasSum.nat_add_neg
.
Alias of HasSum.of_add_one_of_neg_add_one
.
Alias of Summable.of_nat_of_neg
.
"iff" version of Summable.of_nat_of_neg_add_one
.
Equations
- ⋯ = ⋯
Instances For
"iff" version of Multipliable.of_nat_of_neg_add_one
.
"iff" version of Summable.of_nat_of_neg
.
Equations
- ⋯ = ⋯
Instances For
"iff" version of Multipliable.of_nat_of_neg
.