Simple tactics that are used throughout Std. #
_
in tactic position acts like the done
tactic: it fails and gives the list
of goals if there are any. It is useful as a placeholder after starting a tactic block
such as by _
to make it syntactically correct and show the current goal.
Equations
- Std.Tactic.tactic_ = Lean.ParserDescr.node `Std.Tactic.tactic_ 1024 (Lean.ParserDescr.nonReservedSymbol "_" false)
Instances For
Like exact
, but takes a list of terms and checks that all goals are discharged after the tactic.
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Instances For
by_contra h
proves ⊢ p
by contradiction,
introducing a hypothesis h : ¬p
and proving False
.
- If
p
is a negation¬q
,h : q
will be introduced instead of¬¬q
. - If
p
is decidable, it usesDecidable.byContradiction
instead ofClassical.byContradiction
. - If
h
is omitted, the introduced variable_: ¬p
will be anonymous.
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Given a proof h
of p
, absurd h
changes the goal to ⊢ ¬ p
.
If p
is a negation ¬q
then the goal is changed to ⊢ q
instead.
Equations
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Instances For
split_ands
applies And.intro
until it does not make progress.
Equations
- Std.Tactic.tacticSplit_ands = Lean.ParserDescr.node `Std.Tactic.tacticSplit_ands 1024 (Lean.ParserDescr.nonReservedSymbol "split_ands" false)
Instances For
fapply e
is like apply e
but it adds goals in the order they appear,
rather than putting the dependent goals first.
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eapply e
is like apply e
but it does not add subgoals for variables that appear
in the types of other goals. Note that this can lead to a failure where there are
no goals remaining but there are still metavariables in the term:
example (h : ∀ x : Nat, x = x → True) : True := by
eapply h
rfl
-- no goals
-- (kernel) declaration has metavariables '_example'
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Instances For
Deprecated variant of trivial
.
Equations
- Std.Tactic.triv = Lean.ParserDescr.node `Std.Tactic.triv 1024 (Lean.ParserDescr.nonReservedSymbol "triv" false)
Instances For
conv
tactic to close a goal using an equality theorem.
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The conv
tactic equals
claims that the currently focused subexpression is equal
to the given expression, and proves this claim using the given tactic.
example (P : (Nat → Nat) → Prop) : P (fun n => n - n) := by
conv in (_ - _) => equals 0 =>
-- current goal: ⊢ n - n = 0
apply Nat.sub_self
-- current goal: P (fun n => 0)
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